How to configure port for a Spring Boot application

When you need a programatically way of doing it, you can set it during startup:\n\nSystem.getProperties().put( \"server.port\", 80 );\nSpringApplication.run(App.class, args);\n\n\nThis might help for things like environment dependent port. \nHave a nice day",

By default spring boot app start with embedded tomcat server start at default port 8080. spring provides you with following different customization you can choose one of them.\n\n\n NOTE – you can use server.port=0 spring boot will find any unassigned http random port \n for us.\n\n\n1) application.properties\n\nserver.port=2020\n\n\n2) application.yml\n\nserver: \n port : 2020\n\n\n3) Change the server port programatically\n\n3.1) By implementing WebServerFactoryCustomizer interface - Spring 2.x\n\n@Component\npublic class MyTomcatWebServerCustomizer implements WebServerFactoryCustomizer<TomcatServletWebServerFactory> {\n\n @Override\n public void customize(TomcatServletWebServerFactory factory) {\n // customize the factory here\n factory.setPort(2020);\n }\n}\n\n\n3.2) By Implementing EmbeddedServletContainerCustomizer interface - Spring 1.x\n\n@Component\npublic class CustomizationBean implements EmbeddedServletContainerCustomizer {\n\n @Override\n public void customize(ConfigurableEmbeddedServletContainer container) {\n // customize here\n container.setPort(2020);\n }\n}\n\n\n4) By using command line option\n\n java -jar spring-boot-app.jar -Dserver.port=2020\n",

As said in docs either set server.port as system property using command line option to jvm -Dserver.port=8090 or add application.properties in /src/main/resources/ with\nserver.port=8090\n\nFor a random port use:\nserver.port=0\n\nSimilarly add application.yml in /src/main/resources/ with:\nserver:\n port: 8090\n",

if you are using gradle as the build tool, you can set the server port in your application.yml file as:\n\nserver:\n port: 8291\n\n\nIf you are using maven then the port can be set in your application.properties file as:\n\nserver.port: 8291\n",

Indeed, the easiest way is to set the server.port property.\n\nIf you are using STS as IDE, from version 3.6.7 you actually have Spring Properties Editor for opening the properties file.\n\nThis editor provides autocomplete for all Spring Boot properties. If you write port and hit CTRL + SPACE, server.port will be the first option.",

There are two main ways to change the port in the Embedded Tomcat in a Spring Boot Application.\n\nModify application.properties\n\nFirst you can try the application.properties file in the /resources folder:\n\nserver.port = 8090\n\n\n\n\nModify a VM option\n\nThe second way, if you want to avoid modifying any files and checking in something that you only need on your local, you can use a vm arg:\n\nGo to Run -> Edit Configurations -> VM options\n\n-Dserver.port=8090\n\n\n\n\nAdditionally, if you need more information you can view the following blog post here: Changing the port on a Spring Boot Application",

To extend other answers:\n\nThere is a section in the docs for testing which explains how to configure the port on integration tests:\n\n\n41.3 Testing Spring Boot applications\n41.3.3 Working with random ports\n\n\n\n\nAt integration tests, the port configuration is made using the annotation @SpringBootTest and the webEnvironment values.\n\n\n\nRandom port:\n\n@SpringBootTest(webEnvironment=WebEnvironment.RANDOM_PORT)\n\n\nYou can inject the value using @LocalServerPort which is the same as @Value(\"${local.server.port}\").\n\n\nExample:\n\n\nRandom port test configuration:\n\n@RunWith(SpringRunner.class\n@SpringBootTest(webEnvironment = WebEnvironment.RANDOM_PORT)\npublic class ExampleTest {\n ...\n @LocalServerPort //to inject port value\n int port;\n}\n\n\n\n\nDefined port:\n\n@SpringBootTest(webEnvironment=WebEnvironment.DEFINED_PORT)\n\n\nIt takes the value from server.port if is defined.\n\n\nIf is defined using @TestPropertySource(properties = \"server.port=9192\"), it overrides other defined values.\nIf not, it takes the value from src/test/resources/application.properties (if exists). \nAnd finally, if it is not defined it starts with the default 8080.\n\n\nExample:\n\nDefined port test configuration:\n\n@RunWith(SpringRunner.class)\n@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.DEFINED_PORT)\n@TestPropertySource(properties = \"server.port=9192\")\npublic class DemoApplicationTests {\n\n @Test\n public void contextLoads() {\n }\n\n}\n",

By default, spring-web module provides an embedded tomcat server that is running under the port number 8080. If you need to change the port number of the application then go to application.properties file and configure the port number by using server.port property.\n server.port= 9876\n\nthen your application is running under the port 9876.",

Since Spring Boot provides various configuration externalization mechanism (through various PropertySource implementations and/or processors wired into Environment object in order), you can set any property outside of your jar archive through following methods:\n\n\nPass property through command line argument as application argument\n\njava -jar <path/to/my/jar> --server.port=7788\n\nFrom property in SPRING_APPLICATION_JSON (Spring Boot 1.3.0+)\n\n\nDefine environment variable in U*IX shell:\n\nSPRING_APPLICATION_JSON='{\"server.port\":7788}' java -jar <path/to/my/jar>\n\nBy using Java system property:\n\njava -Dspring.application.json='{\"server.port\":7788}' -jar <path/to/my/jar>\n\nPass through command line argument:\n\njava -jar <path/to/my/jar> --spring.application.json='{\"server.port\":7788}'\n\n\nDefine JVM system property\n\njava -Dserver.port=7788 -jar <path/to/my/jar>\n\nDefine OS environment variable\n\n\nU*IX Shell\n\nSERVER_PORT=7788 java -jar <path/to/my/jar>\n\nWindows\n\nSET SERVER_PORT=7788\njava -jar <path/to/my/jar>\n\n\nPlace property in ./config/application.properties configuration file\n\nserver.port=7788\n\n\nand run:\n\n java -jar <path/to/my/jar>\n\nPlace property in ./config/application.yaml\n\nserver:\n port: 7788\n\n\nand run:\n\n java -jar <path/to/my/jar>\n\nPlace property in ./application.properties\n\nserver.port=7788\n\n\nand run:\n\n java -jar <path/to/my/jar>\n\nPlace property in ./application.yaml\n\nserver:\n port: 7788\n\n\nand run:\n\n java -jar <path/to/my/jar>\n\n\n\n\n\nYou can combine above methods all together, and the former configuration in the list take precedence over the latter one.\n\nFor example:\n\nSERVER_PORT=2266 java -Dserver.port=5566 -jar <path/to/my/jar> --server.port=7788\n\n\nThe server will start and listen on port 7788.\n\nThis is very useful providing default properties in PropertySources with lower precedence (and usually packaged in the archive or coded in the source), and then override it in the runtime environment. And it is the design philosophy of Spring Boot:\n\n\n Be opinionated out of the box, but get out of the way quickly as requirements start to diverge from the defaults.\n\n\n\n\nSERVER_NAME to server.name conversion was done by Relaxed Binding.",

You can specify port by overriding EmbeddedServletContainerFactory bean within your configuration (java based or xml). There you can specify port for used embedded servlet container. Please, see Spring Boot - Core \"Embedded Servlet Container Support\" paragraph and example there. Hope this helps.",

Hope this one help\n\n\napplication.properties=> \n\nserver.port=8090\n\napplication.yml=> \n\nserver\n port:8090\n",

Also, you can configure the port programmatically.\nFor Spring Boot 2.x.x:\n@Configuration\npublic class CustomContainer implements WebServerFactoryCustomizer<ConfigurableServletWebServerFactory> {\n public void customize(ConfigurableServletWebServerFactory factory){\n factory.setPort(8042);\n }\n}\n\nFor older versions:\n@Configuration\npublic class ServletConfig {\n @Bean\n public EmbeddedServletContainerCustomizer containerCustomizer() {\n return (container -> {\n container.setPort(8012);\n });\n }\n}\n",

In application.properties file present in resources: \n\nserver.port=8082\n",

Using property server.port=8080 for instance like mentioned in other answers is definitely a way to go. Just wanted to mention that you could also expose an environment property:\n\nSERVER_PORT=8080\n\n\nSince spring boot is able to replace \".\" for \"_\" and lower to UPPER case for environment variables in recent versions.\nThis is specially useful in containers where all you gotta do is define that environment variable without adding/editing application.properties or passing system properties through command line (i.e -Dserver.port=$PORT)",

If you would like to run it locally, use this -\n\nmvn spring-boot:run -Drun.jvmArguments='-Dserver.port=8085'\n\nAs of Spring Boot 2.0, here's the command that works (clues were here):\n\nmvn spring-boot:run -Dspring-boot.run.arguments=--server.port=8085\n",

There are three ways to do it depending on the application configuration file you are using\n\na) If you are using application.properties file set\n\nserver.port = 8090\n\nb) If you are using application.yml file set server port property in YAML format as given below\n\nserver:\n port: 8090\n\n\nc) You can also Set the property as the System property in the main method\n\nSystem.setProperty(\"server.port\",\"8090\");\n",

You can add the port in below methods.\n\n\nRun -> Configurations section\nIn application.xml add server.port=XXXX\n",

You can set port in java code:\n\nHashMap<String, Object> props = new HashMap<>();\nprops.put(\"server.port\", 9999);\n\nnew SpringApplicationBuilder()\n .sources(SampleController.class) \n .properties(props)\n .run(args);\n\n\nOr in application.yml:\n\nserver:\n port: 9999\n\n\nOr in application.properties:\n\nserver.port=9999\n\n\nOr as a command line parameter:\n\n-Dserver.port=9999\n",

There are many other stuffs you can alter in server configuration by changing application.properties.\nLike session time out, address and port etc. Refer below post\n\nref: http://docs.spring.io/spring-boot/docs/1.4.x/reference/html/common-application-properties.html\n\nI used few of them as below. \n\nserver.session.timeout=1\nserver.port = 3029\nserver.address= deepesh\n",

Just have a application.properties in src/main/resources of the project and give there \n\nserver.port=****\n\n\nwhere **** refers to the port number.",

In case you are using application.yml add the Following lines to it\n\nserver:\n port: 9000\n\n\nand of course 0 for random port. ",

Add this in your application.properties file\n\nserver.port= 8080\n",

1.1 Update via a properties file.\n\n/src/main/resources/application.properties\n\nserver.port=8888\n\nUpdate via a yaml file.\n\n server:\n\n port: 8888\n\n\nEmbeddedServletContainerCustomizer\n\n@Component\npublic class CustomContainer implements EmbeddedServletContainerCustomizer {\n\n @Override\n public void customize(ConfigurableEmbeddedServletContainer container) {\n\n container.setPort(8888);\n\n }\n\n}\n",

As explained in Spring documentation, there are several ways to do that:\n\nEither you set the port in the command line (for example 8888)\n\n-Dserver.port=8888 or --server.port=8888\n\nExample : java -jar -Dserver.port=8888 test.jar\n\nOr you set the port in the application.properties\n\nserver.port=${port:4588}\n\n\nor (in application.yml with yaml syntax)\n\nserver:\n port: ${port:4588}\n\n\nIf the port passed by -Dport (or -Dserver.port) is set in command line then this port will be taken into account. If not, then the port will be 4588 by default.\n\nIf you want to enforce the port in properties file whatever the environment variable, you just have to write:\n\nserver.port=8888\n",

\nAs everyone said, you can specify in application.properties \nserver.port = 9000 (could be any other value)\nIf you are using spring actuator in your project, by default it points to\n8080, and if you want to change it, then in application.properties mention \nmanagement.port = 9001 (could be any other value)\n",

Providing the port number in application.properties file will resolve the issue\n\n server.port = 8080\n\n\n\"port depends on your choice, where you want to host the application\"",

Include below property in application.properties\n\nserver.port=8080\n",

In the application.properties file, add this line:\n\nserver.port = 65535\n\nwhere to place that fie:\n\n\n 24.3 Application Property Files\n \n SpringApplication loads properties from application.properties files\n in the following locations and adds them to the Spring Environment:\n\nA /config subdirectory of the current directory\nThe current directory\nA classpath /config package\nThe classpath root\n\n \n The list is ordered by precedence (properties defined in locations\n higher in the list override those defined in lower locations).\n\n\nIn my case I put it in the directory where the jar file stands.\n\nFrom: \n\nhttps://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#boot-features-external-config-application-property-files",

You can set that in application.properties under /src/main/resources/\n\nserver.port = 8090\n",